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9x^2-6x=99
We move all terms to the left:
9x^2-6x-(99)=0
a = 9; b = -6; c = -99;
Δ = b2-4ac
Δ = -62-4·9·(-99)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-60}{2*9}=\frac{-54}{18} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+60}{2*9}=\frac{66}{18} =3+2/3 $
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